Commit 34457f5a by Turnhout, M.C. van

### typesetting

parent d06e16b1
 ... ... @@ -87,7 +87,7 @@ The consequence so far is that interpreting RGB values in terms of amounts of v For starters: twice as much pigment does not mean twice as high a pixel value', on the contrary. More pigment means more absorption and thus \textsl{less} (transmitted) light. Furthermore, when 10\,\% of the light is absorbed, intensity is 90\,\%, and when 20\,\%, twice as much, light is absorbed intensity is 80\,\%: there is a factor 2, but that is not apparent from (the fraction of) the intensity values. To investigate the effects of amounts of pigments' on recorded RGB values, we first have to switch to subtractive colour mixing or absorption space'. The RGB (nominalized) intensity values for yellow are $y_I = [1 1 0]$. Thus, to produce yellow with a pigment we have remove all light but the blue: the RGB \textsl{absorption} values are $y_A = [0 0 1]$. To investigate the effects of amounts of pigments' on recorded RGB values, we first have to switch to subtractive colour mixing or absorption space'. The RGB (nominalized) intensity values for yellow are $y_I = \begin{bmatrix}1 & 1& 0\end{bmatrix}$. Thus, to produce yellow with a pigment we have remove all light but the blue: the RGB \textsl{absorption} values are $y_A = \begin{bmatrix}0 & 0 & 1\end{bmatrix}$. In other words: we have to switch from transmission space' (Intensity, RGB) to absorption space'. ... ...
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